精品深夜AV无码一区二区_伊人久久无码中文字幕_午夜无码伦费影视在线观看_伊人久久无码精品中文字幕

代做COMP9021、代寫Python編程設(shè)計(jì)

時(shí)間:2024-07-20  來源:  作者: 我要糾錯(cuò)



COMP9021 Principles of Programming 
Term 2, 2024 
Assignment 2 
Worth 13marks and due Week 11 Monday @ 10am 
1. General Matters 
 
1.1 Aim 
The purpose of this assignment is to: 
• Develop your problem-solving skills. 
• Design and implement the solution to a problem in the form of a medium sized Python program. 
• Analyse the various features of a labyrinth, represented by a particular coding of its basic elements 
into numbers, from the set {0, 1, 2, 3} only, stored in a text file. 
• Check that the input text file is correct and represents a labyrinth. 
• Output the labyrinth features nicely. 
• Use object-oriented programming. 
 
1.2 Marking 
This assignment is worth 13 marks distributed as follows: 
 2 
 
 
Your program will be tested against several inputs. For each test, the auto-marking script will let your 
program run for 30 seconds. The outputs of your program should be exactly as indicated. 
 
1.3 Due Date and Submission 
Your programs will be stored in a file named labyrinth.py. The assignment can be submitted more than 
once. The last version just before the due date and time will be marked (unless you submit late in which 
case the last late version will be marked). 
Assignment 2 is due Week 11 Monday 5 August 2024 @ 10:00am (Sydney time). 
Please note that late submission with 5% penalty per day is allowed up to 5 days from the due date, that 
is, any late submission after Week 11 Saturday 10 August 2024 @ 10:00am will be discarded. 
Please make sure not to change the filename labyrinth.py while submitting by clicking on [Mark] button in 
Ed. It is your responsibility to check that your submission did go through properly using Submissions link in 
Ed otherwise your mark will be zero for Assignment 2. 
 
1.4 Reminder on Plagiarism Policy 
You are permitted, indeed encouraged, to discuss ways to solve the assignment with other people. Such 
discussions must be in terms of algorithms, not code. But you must implement the solution on your own. 
Submissions are scanned for similarities that occur when students copy and modify other people’s work or 
work very closely together on a single implementation. Severe penalties apply. 
 
2. Description 
The representation of the labyrinth is based on a coding with only the four digits 0, 1, 2 and 3 such that: 
 
• 0 codes points that are connected to neither their right nor their below neighbours: 
• 1 codes points that are connected to their right neighbours but not to their below ones: 
• 2 codes points that are connected to their below neighbours but not to their right ones: 
• 3 codes points that are connected to both their right and below neighbours: 
 
A point that is connected to none of their left, right, above, and below neighbours represents a pillar: 
 
Analysing the labyrinth will also allow to represent: 
 
• cul-de-sac: 
• entry-exit path: 
 3 
 
 
3. Examples 
 
3.1 First Example 
The file named labyrinth_1.txt contains the following: 
 
1 0 2 2 1 2 3 0 
3 2 2 1 2 0 2 2 
3 0 1 1 3 1 0 0 
2 0 3 0 0 1 2 0 
3 2 2 0 1 2 3 2 
1 0 0 1 1 0 0 0 
 
As per the coding above, labyrinth_1.txt will look like the following: 
 
 
Here is a possible interaction: 
 4 
 
 
3.2 Second Example 
The file named labyrinth_2.txt contains the following: 
 
022302120222 
222223111032 
301322130302 
312322232330 
001000100000 
 
As per the coding above, labyrinth_2.txt will look like the following: 
 
 
 
Here is a possible interaction: 
 
 
 
 5 
 
 
3.3 Third Example 
The file named labyrinth_3.txt contains the following: 
 
31111111132 
21122131202 
33023022112 
20310213122 
31011120202 
21230230112 
30223031302 
03122121212 
22203110322 
22110311002 
11111101110 
 
As per the coding above, labyrinth_3.txt will look like the following: 
 
Here is a possible interaction: 
 6 
 
 
3.4 Fourth Example 
The file named labyrinth_4.txt contains the following: 
 
111120 
112020 
002020 
002010 
001110 
 
As per the coding above, labyrinth_4.txt will look like the following: 
 
 
 
Here is a possible interaction: 
 
 
 
 7 
 
 
3.5 Fifth Example 
The file named labyrinth_5.txt contains the following: 
 
 1 1 2 
 1 12 
 
 1 1 0 
 
 
As per the coding above, labyrinth_5.txt will look like the following: 
 
 
 
Here is a possible interaction: 
 
 
 
 8 
 
 
3.6 Sixth Example 
The file named labyrinth_6.txt contains the following: 
 
0111221210021212201201323330200 
1131011210301210323130331302310 
3300200323203011010332232320332 
2330312230220302032203223112310 
1211020213223110101302032332212 
1112222331300131013312312223130 
1110120222130303102210113130100 
0020320223200020113011131202302 
3213100301021111202122030110112 
1200320130030313001031302312110 
0310130300203000312021011212020 
3131210323320222322212332031120 
2021033213003230103112331130222 
1013300313133312220131222100010 
1231322020123133221023110302002 
3322231133223020311032001102310 
2323101332332011010132023031132 
2200112102133112231003320012120 
2130210032120230313010200102112 
2311003320123302322223032120112 
0201320233130133202333323012120 
1003010311132003122332112221132 
2032100103021312110202200332310 
3211202310233321202022122021022 
1200330103010322222131033003000 
1121200200313110310030131100332 
0012021023310003332301123031222 
0120302110232113312232012023020 
2303222021330232031311210131312 
0101112200130031003120203121102 
2012100113233120321011002012220 
0010322001332202013202312122110 
0213000131303132112301110130112 
1222303101032032301032210302110 
1220131300113200003021222120012 
1333010013001231321110022323022 
3021223221133030131221100102210 
2013320130211320203021000311312 
0303003010033021320232203222020 
2030233001202311110121110133220 
1001011011001101100000010100100 
 9 
 
 
As per the coding above, labyrinth_6.txt will look like the following: 
 
 10 
 
 
Here is a possible interaction: 
 
 
 
 11 
 
 
4. Detailed Description 
 
4.1 Input 
The input is expected to consist of ydim lines of xdim members of {0, 1, 2, 3}, where x dim and ydim are at least 
equal to 2 and at most equal to 31 and 41, respectively, with possibly lines consisting of spaces only that 
will be ignored and with possibly spaces anywhere on the lines with digits. 
The xth digit n of the yth line, with 0 ≤ x < xdim and 0 ≤ y < ydim, is to be: 
• associated with a point situated x * 0.5 cm to the right and y * 0.5 cm below an origin, 
• connected to the point 0.5 cm to its right if n = 1 or n = 3, and 
• connected to the point 0.5 cm below itself if n = 2 or n = 3. 
The last digit on every line with digits (that is, not on blank lines) cannot be equal to 1 or 3, and the digits 
on the last line with digits cannot be equal to 2 or 3, which ensures that the input encodes a labyrinth, 
that is, a grid of width (xdim - 1) * 0.5 cm and of height (ydim - 1) * 0.5 cm (hence of maximum width 15 cm 
and of maximum height 20 cm), with possibly gaps on the sides and inside. 
A point not connected to any of its neighbours is thought of as a pillar and a point connected to at least 
one of its neighbours is thought of as part of a wall. 
We talk about inner point to refer to a point that lies (x + 0.5) * 0.5 cm to the right of and (y + 0.5) * 0.5 
cm below the origin with 0 ≤ x < xdim - 1 and 0 ≤ y < ydim - 1. 
Practically, the input will be stored in a text file as shown in the six examples above. The program will exit 
immediately if the input is not as expected. 
 
4.2 Output 
Consider executing from the Python prompt the statement from labyrinth import * followed by the 
statement lab = Labyrinth(filename). In case filename does not exist in the working directory, then Python 
will raise a FileNotFoundError exception, that does not need to be caught. Assume that filename does 
exist (in the working directory). If the input is incorrect in that it does not contain only digits in {0, 1, 2, 3} 
besides spaces, or in that it contains either too few or too many nonblank lines, or in that some nonblank 
lines contain too many or too few digits, or in that two of its nonblank lines do not contain the same 
number of digits, then the effect of executing lab = Labyrinth(filename) should be to generate a 
LabyrinthError exception that reads: 
 
 
 12 
 
 
If the previous conditions hold but the further conditions spelled out above for the input to qualify as a 
labyrinth (that is, the condition on the last digit on every line with digits and the condition on the digits on 
the last line) do not hold, then the effect of executing lab = Labyrinth(filename) should be to generate a 
LabyrinthError exception that reads: 
 
 
 
If the input is correct and represents a labyrinth, then lab = Labyrinth(filename) followed by 
lab.display_features() should have the effect of outputting the following: 
1. the number of gates, that is, the number of consecutive points on one of the four sides of the 
labyrinth that are not connected, 
2. the number of sets of connected walls, 
3. the number of inner points that cannot be accessed from any gate, starting from the point in the 
middle of a gate and going from inner points to neighbouring inner points, 
4. the number of maximal areas that can be accessed from at least one gate (the number of 
accessible inner points is at most equal to the number of gates), 
5. the number of accessible cul-de-sacs (a cul-de-sac is a maximal set S of connected inner points that 
can all be accessed from the same gate g and such that for all points p in S, if p has been accessed 
from g for the first time, then either p is in a dead end or moving on without ever getting back 
leads into a dead end), and 
6. the number of entry-exit paths with no intersections not to cul-de-sacs consisting of a maximal set 
S of connected inner points that go from a gate to another (necessarily different) gate and such that 
for all points p in S, there is only one way to move on from p without getting back and without 
entering a cul-de-sac, in other words, the resulting path is choice-free, that is, such that leaving the 
path, at any inner point where that is possible, immediately leads into a cul-de-sac. 
 
The above should be displayed exactly as described below. 
A first line that reads one of: 
The labyrinth has no gate. 
The labyrinth has a single gate. 
The labyrinth has N gates. 
with N an appropriate integer at least equal to 2. 
 13 
 
 
A second line that reads one of: 
The labyrinth has no wall. 
The labyrinth has walls that are all connected. 
The labyrinth has N sets of walls that are all connected. 
with N an appropriate integer at least equal to 2. 
 
A third line that reads one of: 
The labyrinth has no inaccessible inner point. 
The labyrinth has a unique inaccessible inner point. 
The labyrinth has N inaccessible inner points. 
with N an appropriate integer at least equal to 2. 
 
A fourth line that reads one of: 
The labyrinth has no accessible area. 
The labyrinth has a unique accessible area. 
The labyrinth has N accessible areas. 
with N an appropriate integer at least equal to 2. 
 
A fifth line that reads one of: 
The labyrinth has no accessible cul-de-sac. 
The labyrinth has accessible cul-de-sacs that are all connected. 
The labyrinth has N sets of accessible cul-de-sacs that are all connected. 
with N an appropriate integer at least equal to 2. 
 
A sixth line that reads one of: 
The labyrinth has no entry-exit path with no intersection not to cul-de-sacs. 
The labyrinth has a unique entry-exit path with no intersection not to cul-de-sacs. 
The labyrinth has N entry-exit paths with no intersections not to cul-de-sacs. 
with N an appropriate integer at least equal to 2. 
 
請加QQ:99515681  郵箱:99515681@qq.com   WX:codinghelp





 

標(biāo)簽:

掃一掃在手機(jī)打開當(dāng)前頁
  • 上一篇:DDES9903代寫、代做Python,c/c++編程
  • 下一篇:CIT 593代做、代寫Java/c++語言編程
  • 無相關(guān)信息
    昆明生活資訊

    昆明圖文信息
    蝴蝶泉(4A)-大理旅游
    蝴蝶泉(4A)-大理旅游
    油炸竹蟲
    油炸竹蟲
    酸筍煮魚(雞)
    酸筍煮魚(雞)
    竹筒飯
    竹筒飯
    香茅草烤魚
    香茅草烤魚
    檸檬烤魚
    檸檬烤魚
    昆明西山國家級(jí)風(fēng)景名勝區(qū)
    昆明西山國家級(jí)風(fēng)景名勝區(qū)
    昆明旅游索道攻略
    昆明旅游索道攻略
  • 短信驗(yàn)證碼平臺(tái) 理財(cái) WPS下載

    關(guān)于我們 | 打賞支持 | 廣告服務(wù) | 聯(lián)系我們 | 網(wǎng)站地圖 | 免責(zé)聲明 | 幫助中心 | 友情鏈接 |

    Copyright © 2025 kmw.cc Inc. All Rights Reserved. 昆明網(wǎng) 版權(quán)所有
    ICP備06013414號(hào)-3 公安備 42010502001045

    精品深夜AV无码一区二区_伊人久久无码中文字幕_午夜无码伦费影视在线观看_伊人久久无码精品中文字幕
    <samp id="e4iaa"><tbody id="e4iaa"></tbody></samp>
    <ul id="e4iaa"></ul>
    <blockquote id="e4iaa"><tfoot id="e4iaa"></tfoot></blockquote>
    • <samp id="e4iaa"><tbody id="e4iaa"></tbody></samp>
      <ul id="e4iaa"></ul>
      <samp id="e4iaa"><tbody id="e4iaa"></tbody></samp><ul id="e4iaa"></ul>
      <ul id="e4iaa"></ul>
      <th id="e4iaa"><menu id="e4iaa"></menu></th>
      欧美色精品在线视频| 亚洲综合久久av| 国产欧美一区二区三区网站 | 欧美一区二区视频免费观看| 日日夜夜免费精品视频| 在线观看91av| 久久99精品国产麻豆婷婷| 欧美xxxxx牲另类人与| 国产乱码精品一区二区三| 中文字幕第一区综合| 成年人国产精品| 亚洲一区二区高清| 91精品国产综合久久婷婷香蕉 | 日本乱人伦aⅴ精品| 国产午夜精品在线观看| 色综合久久久久久久久| 国产精品久久久久一区二区三区共| 国产成人99久久亚洲综合精品| 久久久噜噜噜久久人人看| 激情五月激情综合网| 精品理论电影在线观看| 国产在线视频一区二区三区| 欧美大胆人体bbbb| 久久国产夜色精品鲁鲁99| 91麻豆精品国产| 国产在线播精品第三| 中文字幕不卡在线播放| 91在线播放网址| 一区二区久久久| 4438亚洲最大| 国产精品自拍一区| 亚洲三级理论片| 成人影视亚洲图片在线| 日韩欧美国产三级电影视频| 91精品国产综合久久福利| 精品一区二区三区免费观看| 欧美一级生活片| 蜜桃在线一区二区三区| 欧美va天堂va视频va在线| 欧美欧美欧美欧美首页| 精品一区二区av| 亚洲图片激情小说| 91.成人天堂一区| 久久er99热精品一区二区| 天堂久久一区二区三区| 国产精品麻豆欧美日韩ww| 欧美视频三区在线播放| 久久精品国产免费| 中文字幕一区二区视频| 欧美喷水一区二区| 国产69精品久久久久毛片 | 日韩欧美国产三级电影视频| 成人小视频在线| 日韩av电影天堂| 国产精品国产三级国产专播品爱网| 欧美在线一二三四区| 国产乱理伦片在线观看夜一区| 亚洲欧美电影一区二区| 日韩久久精品一区| 91理论电影在线观看| 韩国成人精品a∨在线观看| 亚洲欧美偷拍另类a∨色屁股| 欧美videossexotv100| 欧美性欧美巨大黑白大战| 国产成都精品91一区二区三| 亚洲精品国产第一综合99久久| 日韩一区二区三区四区五区六区| 91麻豆123| 成人午夜在线视频| 九九**精品视频免费播放| 亚洲最大成人网4388xx| 国产精品久久久久久久久久久免费看 | 精品理论电影在线观看| 欧美日韩一级二级三级| 风间由美一区二区三区在线观看 | 一区二区三区日本| 亚洲国产激情av| 久久久三级国产网站| 日韩欧美色综合| 欧美日本在线播放| 欧美日韩综合在线| 日本二三区不卡| 色又黄又爽网站www久久| 成人v精品蜜桃久久一区| 国产成人综合在线观看| 国产成人在线观看| 国产成人免费在线观看不卡| 国产在线麻豆精品观看| 国产一区二区三区精品欧美日韩一区二区三区 | 久久婷婷一区二区三区| 欧美久久久久久久久久| 欧美做爰猛烈大尺度电影无法无天| 成人h动漫精品一区二| 成人av电影在线播放| av一区二区三区| 日本精品视频一区二区| 欧美午夜寂寞影院| 宅男噜噜噜66一区二区66| 欧美一区二区三区四区高清| 日韩精品影音先锋| 久久久99精品免费观看| 国产精品免费看片| 中文字幕日本不卡| 亚洲高清在线精品| 日本v片在线高清不卡在线观看| 日韩电影在线观看电影| 激情五月激情综合网| 国产成a人亚洲精品| 一本一道久久a久久精品| 在线视频一区二区三区| 欧美男男青年gay1069videost | 五月综合激情婷婷六月色窝| 日韩福利电影在线| 国产91清纯白嫩初高中在线观看 | 精品亚洲成a人在线观看| 成人精品视频.| 欧美综合亚洲图片综合区| 在线播放/欧美激情| 欧美国产丝袜视频| 亚洲福利视频一区| 国产一区二区美女诱惑| 欧洲精品一区二区三区在线观看| 日韩精品综合一本久道在线视频| 国产精品久久久久久久久果冻传媒| 亚洲免费观看高清完整版在线| 日韩中文字幕不卡| 懂色av中文字幕一区二区三区| 欧美亚洲国产一区二区三区va| 久久久久久久久久久久久夜| 亚洲综合丝袜美腿| 国产99久久久久久免费看农村| 欧美在线观看一区二区| 日本一区二区在线不卡| 日韩经典一区二区| 色香蕉成人二区免费| 欧美成人精品二区三区99精品| 亚洲免费大片在线观看| 精品一区二区三区视频在线观看| 色美美综合视频| 欧美精彩视频一区二区三区| 日本欧美久久久久免费播放网| 日本福利一区二区| 国产精品区一区二区三区| 蜜桃av一区二区| 欧美日韩在线播| 亚洲免费看黄网站| youjizz久久| 久久久久久久久免费| 日韩成人免费电影| 欧美军同video69gay| 亚洲欧美一区二区不卡| 99精品欧美一区二区蜜桃免费| 国产亚洲1区2区3区| 国产精品一区在线观看乱码| 欧美福利视频一区| 天堂av在线一区| 欧美另类久久久品| 午夜欧美2019年伦理| 欧洲中文字幕精品| 亚洲午夜免费福利视频| 欧美视频一区二区三区四区| 一区二区三区国产精华| 99re66热这里只有精品3直播| 国产精品久久久久久久久快鸭| a在线播放不卡| 亚洲人快播电影网| 91色|porny| 无码av免费一区二区三区试看| 777奇米成人网| 蜜臀av性久久久久蜜臀av麻豆| 在线不卡的av| 久久精品国产澳门| 国产亚洲成aⅴ人片在线观看| 风间由美性色一区二区三区| 中文字幕一区av| 91成人在线免费观看| 亚洲mv在线观看| 日韩午夜在线观看| 国产露脸91国语对白| 精品国产伦一区二区三区观看体验 | 九九九久久久精品| 久久久精品欧美丰满| 国产999精品久久| 玉米视频成人免费看| 3d成人h动漫网站入口| 久久精品72免费观看| 中文文精品字幕一区二区| 99久久综合狠狠综合久久| 亚洲黄色av一区| 日韩欧美一二三区| 成人一区二区视频| 午夜激情久久久| 国产午夜精品一区二区三区视频 | 色悠悠久久综合| 狠狠色2019综合网| 一区二区三区日韩欧美精品| 欧美日韩免费在线视频| 九一九一国产精品| 亚洲视频小说图片| 精品国产一区二区三区不卡|